beautiful soup just get the value inside the tag – Stack Overflow
The following command:
volume = ndAll(“span”, {“id”: “volume”})[0]
gives:
16, 103. 3
when I issue a print(volume).
How do I get just the number?
asked Feb 25 ’14 at 2:15
user1357015user13570159, 59616 gold badges58 silver badges101 bronze badges
0
Extract the string from the element:
answered Feb 25 ’14 at 2:22
Using css selector:
>>> (‘span#volume’)[0]
u’16, 103. 3′
answered Feb 25 ’14 at 2:23
falsetrufalsetru324k51 gold badges635 silver badges570 bronze badges
answered Mar 28 ’18 at 10:19
cinv3cinv3914 bronze badges
Just to add, I also found the dosn’t do well when there is
in the text.
EG:
Second Line
Third Line
If we do a (“div”, attrs={“class”:”Lines}) we get a None
But a (“div”, attrs={“class”:”Lines}) we get
First Line
Second Line
Third Line
I think the gives a NavigatableString object and gives a unicode object.
answered Mar 31 ’20 at 7:41
There is a function for getting the value of the tag: ntents[0]
Try this:
volumes = soup(‘span’)
for volume in volumes:
print(ntents[0])
answered Sep 7 ’20 at 17:19
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Extracting an attribute value with beautifulsoup in Python
Prerequisite: Beautifulsoup InstallationAttributes are provided by Beautiful Soup which is a web scraping framework for Python. Web scraping is the process of extracting data from the website using automated tools to make the process faster. A tag may have any number of attributes. For example, the tag has an attribute “class” whose value is “active”. We can access a tag’s attributes by treating it like a
Implementation:Example 1: Program to extract the attributes using attrs approach. Python3from bs4 import BeautifulSoupsoup = BeautifulSoup(, “lxml”)tag = soup. h2attribute = trsprint(attribute)Output: {‘class’: [‘hello’]}
Example 2: Program to extract the attributes using dictionary approach. Python3from bs4 import BeautifulSoupsoup = BeautifulSoup(, “lxml”)tag = soup. h2attribute = tag[‘class’]print(attribute)Output: [‘hello’]
Example 3: Program to extract the multiple attribute values using dictionary thon3from bs4 import BeautifulSoupsoup = BeautifulSoup(, “lxml”)tag = soup. h2attribute = tag[‘class’]print(attribute)Output: [‘first’, ‘second’, ‘third’]
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Extracting an attribute value with beautifulsoup – Stack Overflow
I am trying to extract the content of a single “value” attribute in a specific “input” tag on a webpage. I use the following code:
import urllib
f = urllib. urlopen(“)
s = ()
()
from BeautifulSoup import BeautifulStoneSoup
soup = BeautifulStoneSoup(s)
inputTag = ndAll(attrs={“name”: “stainfo”})
output = inputTag[‘value’]
print str(output)
I get a TypeError: list indices must be integers, not str
even though from the Beautifulsoup documentation i understand that strings should not be a problem here… but i a no specialist and i may have misunderstood.
Any suggestion is greatly appreciated!
asked Apr 10 ’10 at 6:53. find_all() returns list of all found elements, so:
input_tag = nd_all(attrs={“name”: “stainfo”})
input_tag is a list (probably containing only one element). Depending on what you want exactly you either should do:
output = input_tag[0][‘value’]
or use () method which returns only one (first) found element:
input_tag = (attrs={“name”: “stainfo”})
output = input_tag[‘value’]
answered Apr 10 ’10 at 7:06
ŁukaszŁukasz31. 2k4 gold badges31 silver badges32 bronze badges
6
In Python 3. x, simply use get(attr_name) on your tag object that you get using find_all:
xmlData = None
with open(‘conf//’, ‘r’) as xmlFile:
xmlData = ()
xmlDecoded = xmlData
xmlSoup = BeautifulSoup(xmlData, ”)
repElemList = nd_all(‘repeatingelement’)
for repElem in repElemList:
print(“Processing repElem… “)
repElemID = (‘id’)
repElemName = (‘name’)
print(“Attribute id =%s”% repElemID)
print(“Attribute name =%s”% repElemName)
against XML file conf// that looks like:
prints:
Processing repElem…
Attribute id = 11
Attribute name = Joe
Attribute id = 12
Attribute name = Mary
answered Nov 16 ’16 at 19:36
amphibientamphibient26k47 gold badges132 silver badges222 bronze badges
3
If you want to retrieve multiple values of attributes from the source above, you can use findAll and a list comprehension to get everything you need:
inputTags = ndAll(attrs={“name”: “stainfo”})
### You may be able to do findAll(“input”, attrs={“name”: “stainfo”})
output = [x[“stainfo”] for x in inputTags]
print output
### This will print a list of the values.
glglgl83k11 gold badges132 silver badges205 bronze badges
answered Aug 28 ’12 at 15:35
MargathMargath611 silver badge5 bronze badges
0
I would actually suggest you a time saving way to go with this assuming that you know what kind of tags have those attributes.
suppose say a tag xyz has that attritube named “staininfo”..
full_tag = ndAll(“xyz”)
And i wan’t you to understand that full_tag is a list
for each_tag in full_tag:
staininfo_attrb_value = each_tag[“staininfo”]
print staininfo_attrb_value
Thus you can get all the attrb values of staininfo for all the tags xyz
Avijit2812 silver badges20 bronze badges
answered Jul 8 ’12 at 12:20
b1tchackedb1tchacked4204 silver badges12 bronze badges
you can also use this:
import requests
from bs4 import BeautifulSoup
import csv
url = ”
r = (url)
data =
soup = BeautifulSoup(data, “”)
get_details = nd_all(“input”, attrs={“name”:”stainfo”})
for val in get_details:
get_val = val[“value”]
print(get_val)
answered Oct 18 ’17 at 18:40
1
For me:
This can be fetched by below snippet.
page = (“)
soup = BeautifulSoup(ntent, ”)
colorName = (id=’color’)
print(colorName[‘value’])
zcoop982, 1681 gold badge12 silver badges25 bronze badges
answered Aug 24 ’20 at 14:37
vijayraj34vijayraj341, 05115 silver badges20 bronze badges
2
You could try to use the new powerful package called requests_html:
from requests_html import HTMLSession
session = HTMLSession()
r = (“)
date = (‘time’, first = True) # finding a “tag” called “time”
print(date) # you will have:
# To get the text inside the “datetime” attribute use:
print([‘datetime’]) # you will get ‘2020-10-07T11:41:22. 000Z’
answered Oct 7 ’20 at 18:14
Yasser MYasser M1711 silver badge6 bronze badges
I am using this with Beautifulsoup 4. 8. 1 to get the value of all class attributes of certain elements:
html = “
bsoup = BeautifulSoup(html, ”)
for td in nd_all(‘td’):
if td. has_attr(‘class’):
print(td[‘class’][0])
Its important to note that the attribute key retrieves a list even when the attribute has only a single value.
answered Nov 17 ’19 at 21:30
PeterXXPeterXX4484 silver badges13 bronze badges
Here is an example for how to extract the href attrbiutes of all a tags:
import requests as rq
from bs4 import BeautifulSoup as bs
page = (url)
html = bs(, ‘lxml’)
hrefs = nd_all(“a”)
all_hrefs = []
for href in hrefs:
# print((“href”))
links = (“href”)
(links)
print(all_hrefs)
omajid10. 7k4 gold badges39 silver badges55 bronze badges
answered Dec 18 ’20 at 13:46
You can try gazpacho:
Install it using pip install gazpacho
Get the HTML and make the Soup using:
from gazpacho import get, Soup
soup = Soup(get(“)) # get directly returns the html
inputs = (‘input’, attrs={‘name’: ‘stainfo’}) # Find all the input tags
if inputs:
if type(inputs) is list:
for input in inputs:
print((‘value’))
else:
print(‘No tag found with the attribute name=”stainfo”)
answered Oct 28 ’20 at 5:10
VthechampVthechamp5255 silver badges16 bronze badges
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Frequently Asked Questions about beautifulsoup get value of tag
How do you get a tag attribute value in Beautiful Soup?
close() from BeautifulSoup import BeautifulStoneSoup soup = BeautifulStoneSoup(s) inputTags = soup. findAll(attrs={“name” : “stainfo”}) ### You may be able to do findAll(“input”, attrs={“name” : “stainfo”}) output = [x[“stainfo”] for x in inputTags] print output ### This will print a list of the values.Nov 17, 2016
How do you get a class value in Beautiful Soup?
Create an HTML doc. Import module. Parse the content into BeautifulSoup. Iterate the data by class name….Approach:Import module.Make requests instance and pass into URL.Pass the requests into a Beautifulsoup() function.Then we will iterate all tags and fetch class name.Nov 26, 2020
How do you get a href value in Beautiful Soup?
Use Beautiful Soup to extract href linkshtml = urlopen(“http://kite.com”)soup = BeautifulSoup(html. read(), ‘lxml’)links = []for link in soup. find_all(‘a’):links. append(link. get(‘href’))print(links[:5]) print start of list.